Ratio between electron to proton

[waver.]

Homework Statement

A 10 gram silver sphere is charged until it acquired a charge of -1.2 coulomb. Find ratio of number of electron to number of proton in spere. Given that silver atomic weight and atomic number 107.87 and 47

Homework Equations

The Attempt at a Solution

first i calculated extra electron = -1.2/1.60217657 × 10-19
Since number of proton = number of elelectron before acquired charge . Number of new electron = 47 +1.2/1.60217657 × 10-19.. and then dividing it by 47 . To get the ratio . My question is that correct what i did . And if yes we he mentioned mass of silver and atomic weight.

 

[mfb]

What is the old number of electrons of the whole sphere? The sphere has more than one atom and the number of atoms depends on the weight.

 

[waver.]

So 107.87 gm --------->6.0221413*10^23 atom
10 gm ------> x atom
then multiply x with 47 to get whole electrons . Then getting extra electron through q= ne adding it to electron number then dividing it by x*47 (proton) . Is that what you meant

 

[lightgrav]

yes.

 

[waver.]

Well . Thnx for helping . That was kind :)