Ratio between electron to proton

AI Thread Summary
To find the ratio of electrons to protons in a charged silver sphere, the calculation begins with determining the number of excess electrons from the charge of -1.2 coulombs, using the charge of a single electron. The initial number of electrons equals the number of protons in neutral silver, which is 47. The total number of electrons is then adjusted by adding the excess electrons to the initial count. The mass of the sphere is relevant for calculating the total number of atoms, which is derived from its atomic weight and Avogadro's number, ultimately leading to the total number of protons for the ratio calculation. The discussion confirms that the method for calculating the ratio is correct and emphasizes the importance of considering the sphere's mass and atomic structure.
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Homework Statement


A 10 gram silver sphere is charged until it acquired a charge of -1.2 coulomb. Find ratio of number of electron to number of proton in spere. Given that silver atomic weight and atomic number 107.87 and 47

Homework Equations

The Attempt at a Solution


first i calculated extra electron = -1.2/1.60217657 × 10-19
Since number of proton = number of elelectron before acquired charge . Number of new electron = 47 +1.2/1.60217657 × 10-19.. and then dividing it by 47 . To get the ratio . My question is that correct what i did . And if yes we he mentioned mass of silver and atomic weight.
 
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What is the old number of electrons of the whole sphere? The sphere has more than one atom and the number of atoms depends on the weight.
 
So 107.87 gm --------->6.0221413*10^23 atom
10 gm ------> x atom
then multiply x with 47 to get whole electrons . Then getting extra electron through q= ne adding it to electron number then dividing it by x*47 (proton) . Is that what you meant
 
yes.
 
Well . Thnx for helping . That was kind :)
 
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