- #1

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[tex] \frac{Q}{C}=R \frac{dq}{dt}[/tex]

Solving this equation we get

[tex] q(t)= Q_{0} exp \frac{t}{RC} [/tex]

Obviously, this isn't the solution. It is actually [tex] q(t)= Q_0 exp \frac{-t}{RC} [/tex]. So, I'm missing a minus sign on the original equation.

But why should it be there?