Reducing Circuits to Their Simplest Form

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Homework Help Overview

The discussion revolves around identifying which circuits can be simplified to a single resistance and a battery by determining the equivalent resistance through series and parallel combinations of resistors. The subject area is electrical circuits, specifically focusing on resistor configurations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the elimination of certain circuits based on perceived impossibilities of reduction. There is mention of using transformations such as delta to Y for circuit simplification. Some participants express uncertainty about the terminology and concepts involved.

Discussion Status

The discussion is active, with participants providing hints and clarifications regarding circuit configurations. There is a recognition of different approaches to analyzing the circuits, and while some guidance has been offered, there is no explicit consensus on the correct answer yet.

Contextual Notes

Participants are navigating through the complexities of circuit reduction, with some constraints noted regarding the definitions of series and parallel connections. The original poster's understanding of the circuits is being challenged, leading to further exploration of the problem.

sweetdion
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Homework Statement


Which of the following circuits could be reduced to a single resistance and a battery by determining the equivalent resistance using combinations of resistors in series and parallel?
Screenshot.png


A. II and IV only
B. I and II only
C. II and III only
D. I and III only
E. I and IV only


Homework Equations



Parallel: 1/Req = 1/R1+1/R2+...
Series: Req= R1+R2+...

The Attempt at a Solution



I think 3 and 4 can be eliminated because it seems impossible that you can reduce those to just one resistor.

So I'm thinking the answer is I and II only, but I'm unsure.
 
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Take a closer look at 4. Redraw it (hint: it'll have 3 parallel resistor branches).
For 2, are you planning to use the delta to Y transformation?
 
Melawrghk said:
Take a closer look at 4. Redraw it (hint: it'll have 3 parallel resistor branches).
For 2, are you planning to use the delta to Y transformation?

I don't even know what you mean by the delta to Y transformation :redface:
 
sweetdion said:
I don't even know what you mean by the delta to Y transformation :redface:

Don't worry about it then :) It's a transformation that would allow you to change circuit 2 into battery+resistor circuit. Since you said you thought it could be solved, how did you plan on reducing on?
 
well the resistors on the outer edges of the diamond are in series. You can reduce those to one resistor each. Then you have 3 resistors in parallel which you can reduce...i think
 
sweetdion said:
well the resistors on the outer edges of the diamond are in series. You can reduce those to one resistor each. Then you have 3 resistors in parallel which you can reduce...i think

For circuit 2? That wouldn't be correct. Every resistor is connected to nodes (point where 3 or more wires meet) at both of its ends. You can only claim that resistors are in series if they do not have a node inbetween them.
---R1----R2---- Resistors 1 and 2 are in series

---R1---R2---- Resistors 1 and 2 are NOT in series
''''''''''''''|
'''''''''''''R3
'''''''''''''|

That is however the correct approach for circuit 4.
 
Okay, So I see what your saying. The correct answer would be E. I and IV, unless I've got something wrong out of your explanations...
 

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