Refraction at grazing incidence

AI Thread Summary
The discussion centers on understanding refraction at grazing incidence, particularly when light transitions from air into a glass cube. The key point is that at grazing incidence, the angle of incidence is slightly less than 90 degrees, allowing the light to enter the glass rather than continuing straight into the water. The calculations involve using Snell's law to determine the angles of refraction, with the refracted ray then traveling within the glass before refracting again at the water interface. Participants clarify that the position of light entry into the cube is arbitrary, addressing confusion about the ray's path. Ultimately, the discussion emphasizes the importance of accurately applying the principles of refraction in this scenario.
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Homework Statement



I have a problem with the question in the attachment below. I have no idea on how to proceed as I thought that the ray of light would continue to travel in a straight line with no refraction whatsoever.

Homework Equations



n1sinθ1=n2sin2

The Attempt at a Solution



I am lost on this one!
 

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nilic1 said:

Homework Statement



I have a problem with the question in the attachment below. I have no idea on how to proceed as I thought that the ray of light would continue to travel in a straight line with no refraction whatsoever.

Homework Equations



n1sinθ1=n2sin2

The Attempt at a Solution



I am lost on this one!

The angles of incidence and refraction are defined as angles enclosed by the rays and the normal of the interface. Grazing incidence means θ1=90°. What angle does the refracted ray enclose with the normal of the face of cube?

ehild
 
ehild said:
The angles of incidence and refraction are defined as angles enclosed by the rays and the normal of the interface. Grazing incidence means θ1=90°. What angle does the refracted ray enclose with the normal of the face of cube?

ehild

My new attempt is:

n1 sinθ1 = n2sinθ2
1.55 x sin90 = 1.33 x sin θ2
1.55/1.33 = sin θ2
1.165 = sin θ2
∴ something is wrong!
 
The light enters from air. What is n1 then?

ehild
 
n = 1 for air.

so the working changes to

n1 sinθ1 = n2 sinθ2
1 x sin 90 = 1.33 x sinθ2
1/1.33 = sinθ2

θ2 = 48.5 degrees

I am still puzzled ... so when angle i = 90, the medium is air and not glass. If this is so then is the glass cube is irrelevant for the question? If so wouldn't the ray of light go straight and not be bent at the water surface or in the water?

According to the answer in the book the angle in part b ii is 62.9 degrees. Still cannot figure out the path taken by the ray of light. I appreciate your help ehild.
 
ok finally I got it... but my question still is .. Why doesn't the ray continue to travel in a straight line?
 
Last edited:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild
 

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ehild said:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild

So grazing is slightly less than 90 degrees... That explains everything! Thank you so much ehild.
 
You are welcome:smile:

ehild
 
  • #10
ehild said:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild
How do you know from which point the light ray is entering inside the glass cube? Is the pictorial representation of the question
wrong? I mean why isn't the light ray entering first at the upper left corner of the cube ?
 
  • #11
Rongeet Banerjee said:
How do you know from which point the light ray is entering inside the glass cube? Is the pictorial representation of the question
wrong? I mean why isn't the light ray entering first at the upper left corner of the cube ?
The position where the light enters the glass cube is arbitrarily chosen.
 
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