Refraction at grazing incidence

Click For Summary

Homework Help Overview

The discussion revolves around the phenomenon of refraction at grazing incidence, particularly focusing on the behavior of light as it transitions from air into a glass cube and subsequently into water. Participants are exploring the implications of the angles of incidence and refraction, specifically when the angle of incidence approaches 90 degrees.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants express confusion regarding the expected behavior of light at grazing incidence, with some questioning the relevance of the glass cube in the scenario. Others attempt to apply Snell's law but encounter inconsistencies in their calculations.

Discussion Status

The discussion is active, with participants sharing their attempts at applying the relevant equations and seeking clarification on the nature of grazing incidence. Some have provided insights into the angles involved, while others are still grappling with the conceptual understanding of the light's path.

Contextual Notes

There is an ongoing debate about the definition of grazing incidence and its implications for the path of light, as well as the assumptions made regarding the entry point of the light ray into the glass cube.

nilic1
Messages
39
Reaction score
0

Homework Statement



I have a problem with the question in the attachment below. I have no idea on how to proceed as I thought that the ray of light would continue to travel in a straight line with no refraction whatsoever.

Homework Equations



n1sinθ1=n2sin2

The Attempt at a Solution



I am lost on this one!
 

Attachments

  • Image4.jpg
    Image4.jpg
    28 KB · Views: 716
Physics news on Phys.org
nilic1 said:

Homework Statement



I have a problem with the question in the attachment below. I have no idea on how to proceed as I thought that the ray of light would continue to travel in a straight line with no refraction whatsoever.

Homework Equations



n1sinθ1=n2sin2

The Attempt at a Solution



I am lost on this one!

The angles of incidence and refraction are defined as angles enclosed by the rays and the normal of the interface. Grazing incidence means θ1=90°. What angle does the refracted ray enclose with the normal of the face of cube?

ehild
 
ehild said:
The angles of incidence and refraction are defined as angles enclosed by the rays and the normal of the interface. Grazing incidence means θ1=90°. What angle does the refracted ray enclose with the normal of the face of cube?

ehild

My new attempt is:

n1 sinθ1 = n2sinθ2
1.55 x sin90 = 1.33 x sin θ2
1.55/1.33 = sin θ2
1.165 = sin θ2
∴ something is wrong!
 
The light enters from air. What is n1 then?

ehild
 
n = 1 for air.

so the working changes to

n1 sinθ1 = n2 sinθ2
1 x sin 90 = 1.33 x sinθ2
1/1.33 = sinθ2

θ2 = 48.5 degrees

I am still puzzled ... so when angle i = 90, the medium is air and not glass. If this is so then is the glass cube is irrelevant for the question? If so wouldn't the ray of light go straight and not be bent at the water surface or in the water?

According to the answer in the book the angle in part b ii is 62.9 degrees. Still cannot figure out the path taken by the ray of light. I appreciate your help ehild.
 
ok finally I got it... but my question still is .. Why doesn't the ray continue to travel in a straight line?
 
Last edited:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild
 

Attachments

  • glasswater.JPG
    glasswater.JPG
    13.8 KB · Views: 605
ehild said:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild

So grazing is slightly less than 90 degrees... That explains everything! Thank you so much ehild.
 
You are welcome:smile:

ehild
 
  • #10
ehild said:
The ray enters from air onto the surface of the glass cube. That grazing incidence means that it makes an angle a bit less than 90° with the normal, so it really strikes the air/glass surface and enters into the glass, instead going straight into the water. The refracted ray travels inside the glass cube and falls onto the bottom face at a certain angle. Here it is refracted again, from glass into water. Draw the path of the ray and calculate the angles.

ehild
How do you know from which point the light ray is entering inside the glass cube? Is the pictorial representation of the question
wrong? I mean why isn't the light ray entering first at the upper left corner of the cube ?
 
  • #11
Rongeet Banerjee said:
How do you know from which point the light ray is entering inside the glass cube? Is the pictorial representation of the question
wrong? I mean why isn't the light ray entering first at the upper left corner of the cube ?
The position where the light enters the glass cube is arbitrarily chosen.
 
  • Like
Likes   Reactions: Rongeet Banerjee

Similar threads

  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
5K
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K