Regarding continuous random variable

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SUMMARY

The discussion focuses on finding the expected value E(Y) of a continuous random variable Y defined as Y=e^X, where X follows a uniform distribution over the interval [-a, a]. The key formula for the expectation of a continuous random variable is highlighted as E(Y) = ∫_{-∞}^{+∞} Y f(Y) dY, with f(Y) being the probability density function. The user seeks assistance in progressing from the initial expression E(Y) = E(e^X) to a complete solution.

PREREQUISITES
  • Understanding of uniform distribution, specifically uniform distribution over the interval [-a, a]
  • Knowledge of continuous random variables and their properties
  • Familiarity with the concept of expectation in probability theory
  • Basic calculus, particularly integration techniques
NEXT STEPS
  • Study the derivation of the expectation for functions of random variables, specifically E(e^X)
  • Learn about the probability density function for uniform distributions
  • Explore integration techniques for evaluating definite integrals
  • Investigate the moment-generating function and its applications in probability
USEFUL FOR

Students and professionals in statistics, data science, and mathematics, particularly those working with probability distributions and expectations of continuous random variables.

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Here's the qn random variable X follows uniform distribution [-a,a] and random variable Y is defined as Y=e^x find E(Y)

i figure that E(Y)=E(e^x) but somehow can't carry on from there can anyone help?
 
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The expectation of a continuous random variable Y is defined by [tex]\int_{-\infty}^{+\infty}xf(x)dx[/tex], where f(x) is the probability density function of the random variable Y. Follow the definition. :smile:
 

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