Regarding Gravitation and Gravitational Fields

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SUMMARY

The discussion focuses on calculating the orbital parameters of a satellite designed to orbit Earth at a gravitational field strength of 4.5 N/kg. The user successfully calculated the altitude of the satellite as 3.0 x 103 km using the equation g=(G*Me)/r2. For the acceleration and speed calculations, the user is advised to derive the velocity from centripetal force and gravitational force relationships, confirming that the acceleration due to gravity varies with altitude and is not constant at 9.8 m/s2 in this context.

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  • Understanding of gravitational force and acceleration equations
  • Familiarity with centripetal force concepts
  • Knowledge of orbital mechanics
  • Proficiency in algebraic manipulation of equations
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  • Learn how to apply Newton's law of universal gravitation in orbital mechanics
  • Explore the concept of gravitational potential energy in satellite orbits
  • Investigate the effects of altitude on gravitational acceleration
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Students studying physics, particularly those focusing on gravitational fields and orbital mechanics, as well as educators seeking to clarify satellite motion concepts.

nblu
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Homework Statement



A satellite is designed to orbit Earth at an altitude above its surface that will place it in a gravitational field with a strength of 4.5N/kg.
a) Calculate the distance above the surface of Earth at which the satellite must orbit.
b) Assuming the orbit is circular, calculate the acceleration of the satellite and its direction.
c) At what speed must the satellite travel in order to maintain this orbit?

Homework Equations


g=(G*Me)/r^2, where Me is Earth's mass

The Attempt at a Solution


For a), I've used the above equation, with given g value(4.5) substituted into the equation, and got 3.0 x 10^3km as my final answer but b) and c) is where I have the problem. In order to calculate the acceleration for b), I believe that I need to calculate the velocity(v=sqrt(G*Me/r)) first then substitute into (a = v^2/r). However, if I end up getting an answer for part b), didn't I just do c) as well? Because for c) I need to calculate the velocity as well.. I'd like to know whether or not I was wrong about this before I get in any further.

Thank you in advance for your comments.
 
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Hint:
orbital motion is "free-fall." What is the acceleration of free fall?
 
The way you calculated b) is not wrong, and it will work. However, how did you arrive at your equation for velocity? To derive it, you would start by equating centripetal force with gravitational force. What is the centripetal acceleration? Can you figure it out without first calculating velocity?
 
acceleration in free-fall is 9.8m/s/s right?
 
Only near the surface of the earth, because the gravitational force is GMm/r2 = mg = 9.8m on the surface.
 
nblu said:
acceleration in free-fall is 9.8m/s/s right?

only where g is 9.8 N/kg
 

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