Regarding Gravitation and Gravitational Fields

AI Thread Summary
A satellite must orbit Earth at an altitude where the gravitational field strength is 4.5 N/kg, which requires calculating the distance above Earth's surface using the equation g=(G*Me)/r^2. The discussion highlights that to find the acceleration of the satellite, one can first determine its velocity using the equation v=sqrt(G*Me/r) and then apply it to the centripetal acceleration formula a = v^2/r. Clarification is sought on whether calculating acceleration also resolves the speed requirement for maintaining orbit. The conversation emphasizes the importance of understanding gravitational force and centripetal force in orbital motion. Overall, the calculations for both acceleration and speed are interconnected and can be derived from the same principles.
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Homework Statement



A satellite is designed to orbit Earth at an altitude above its surface that will place it in a gravitational field with a strength of 4.5N/kg.
a) Calculate the distance above the surface of Earth at which the satellite must orbit.
b) Assuming the orbit is circular, calculate the acceleration of the satellite and its direction.
c) At what speed must the satellite travel in order to maintain this orbit?

Homework Equations


g=(G*Me)/r^2, where Me is Earth's mass

The Attempt at a Solution


For a), I've used the above equation, with given g value(4.5) substituted into the equation, and got 3.0 x 10^3km as my final answer but b) and c) is where I have the problem. In order to calculate the acceleration for b), I believe that I need to calculate the velocity(v=sqrt(G*Me/r)) first then substitute into (a = v^2/r). However, if I end up getting an answer for part b), didn't I just do c) as well? Because for c) I need to calculate the velocity as well.. I'd like to know whether or not I was wrong about this before I get in any further.

Thank you in advance for your comments.
 
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Hint:
orbital motion is "free-fall." What is the acceleration of free fall?
 
The way you calculated b) is not wrong, and it will work. However, how did you arrive at your equation for velocity? To derive it, you would start by equating centripetal force with gravitational force. What is the centripetal acceleration? Can you figure it out without first calculating velocity?
 
acceleration in free-fall is 9.8m/s/s right?
 
Only near the surface of the earth, because the gravitational force is GMm/r2 = mg = 9.8m on the surface.
 
nblu said:
acceleration in free-fall is 9.8m/s/s right?

only where g is 9.8 N/kg
 
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