Related Rates: Particle Moving Along y=x^1/3, x=8, Theta Approx. 0.24 Rad

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A particle is moving along the graph of y=x^1/3.  
Suppose x is increasing at the rate of 3 cm/s.  
At what rate is the angle of inclination, theta, changing when x=8?  
[Hint: when x=8, theta approx. 0.24 rad]
I'm stuck on problem. I know x=8, y=2 and the hyp=2.87. They want the derivative of theta so am I supposed to take the derivative of theta=0.24?
 
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No, you want to find some function that defines theta, and take the derivative of that.
 
NIZBIT said:
Code:
A particle is moving along the graph of y=x^1/3.  
Suppose x is increasing at the rate of 3 cm/s.  
At what rate is the angle of inclination, theta, changing when x=8?  
[Hint: when x=8, theta approx. 0.24 rad]
I'm stuck on problem. I know x=8, y=2 and the hyp=2.87. They want the derivative of theta so am I supposed to take the derivative of theta=0.24?
Well, the derivative of a constant (0.24) is 0 so that wouldn't do a whole lot of good would it? :wink: It's a lot more helpful to find the derivative of a function rather than a number! Draw a picture, showing the "angle of inclination" and write theta as a function of x. Then find the derivative of that function with respect to x. (Do you remember that the derivative of a function is the tangent of the angle the tangent line to the graph makes with the x-axis?)
 
yo.gif

Is this correct? Or am I completely off my rocker?:frown:
 
You're off your rocker. :biggrin:

Try following these steps:

1.) Draw a graph of f(x)=x1/3 vs. x.

2.) Consider an arbitrary point on the curve: (x,y)=(x,x1/3)

3.) Draw a line segment from the origin to (x,y) and drop a vertical line segment down from (x,y) to the x-axis. You now have a right triangle.

4.) The angle made by the line segment (the one connecting (0,0) to (x,y)) and the x-axis is the angle of inclination. Write down an expression for it in terms of x.

Try that and let's see what you come up with.
 
yup.gif

Is this right?
 
So far so good, but you're supposed to plug in x=8 and get a number for d\theta/dt.
 
Sweet! Thanks to all for the help!
 
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