Related Rates Sand Pile Problem

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Homework Statement


A machine starts dumping sand at the rate of 20 m3/min, forming a pile in the shape of a cone. The height of the pile is always twice the length of the base diameter. After 5 minutes, how fast is the height increasing? After 5 minutes, how fast is the area of the base increasing?

Homework Equations



V = (1/3)(pi)r^2(h)

The Attempt at a Solution


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For the first question,
##h = 4r##
##\displaystyle V(t) = 20t = \frac{1}{3}\pi r^2 h = \frac{\pi}{48}h^3##
From this equation I get
##\displaystyle h = (\frac{960}{\pi}t)^{\frac{1}{3}}##
then
##\frac{dh}{dt} = \frac{320}{\pi ((\frac{960}{\pi})t)^{\frac{2}{3}}}##
When 5 is substituted for t, I get 0.77 m^3/min. Is this correct?

Also, I am not sure how to approach the second problem. I know that the area of the base is ##\pi r^2##, but I am not sure how to proceed...
 
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Use the fact that height is equal to twice the diameter of the base at all times.
 
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Thewindyfan said:
Use the fact that height is equal to twice the diameter of the base at all times.
I did that for the first problem. I don't see how it will work for the second problem though.
 
Mr Davis 97 said:
I did that for the first problem. I don't see how it will work for the second problem though.
EDIT: ah never mind, fairly straightforward problem. Haven't seen one like this in awhile though.

Method 1: If you're know what dH/dt is, try applying that to see what the radius would be.

EDIT: you did the first part right.
Suggested Hint: Try rewriting the area equation.

...and check your units to part 1.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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