Relationship of acceleration in two-pulley system

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SUMMARY

The relationship between the accelerations a1 and a2 in a two-pulley system is established as a1 = 2a2. This conclusion arises from analyzing the distances moved by the masses m1 and m2, where m1 moves twice the distance of m2 due to the configuration of the pulleys. The discussion highlights the importance of understanding the relationship between the lengths of the segments of the string and the corresponding accelerations. The correct answer is confirmed through iterative attempts and clarifications among participants.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of pulley systems and their mechanics
  • Familiarity with kinematic equations, particularly S = 1/2 at²
  • Concept of tension distribution in a two-pulley system
NEXT STEPS
  • Study the mechanics of pulley systems in detail
  • Learn about tension forces in multi-pulley arrangements
  • Explore kinematic relationships in systems with multiple masses
  • Investigate the derivation of acceleration relationships in pulley systems
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking to clarify concepts related to pulley systems and acceleration relationships.

jake jungle
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Homework Statement


upload_2015-2-4_20-24-52.png

What is the relationship between a1 and a2
A.a1=a2
B.a1=2a2
C.a2=2a1
D.a1=a2√2
E.a2=a1√2
F.There is no simple relationship between the two acceleration

Homework Equations


a = F/m

The Attempt at a Solution


I am quite confused with the second pulley , so the weight of m2 is divided to 2 tension through the second pulley , but i can't find what is the magnitude of the upper tension ,therefore we can't find the lower tension or the acceleration either.
So i choose F as my answer , however i am not sure . Is my answer right ?.
 
Last edited:
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Conserve string.
 
DEvens said:
Conserve string.

sorry i don't get it . can you be more specific , and which answer do you choose :D
 
Really? That's not enough?

Ok. When mass m1 moves a distance of 1 unit, how far must the mass m2 move?
 
That's where i was confused.
If m2 goes a distance of x. Will m1 goes a distance of x/2 or 2x?
 
jake jungle said:
That's where i was confused.
If m2 goes a distance of x. Will m1 goes a distance of x/2 or 2x?
Let the lengths of the horizontal portions be x (on the left), y (top right), z (lower right).
What equations relate them?
 
I have the same problem too
haruspex said:
Let the lengths of the horizontal portions be x (on the left), y (top right), z (lower right).
What equations relate them?

I think that it is Δx = Δy + Δz
Since Δy is the same as Δz, so Δx = 2Δy = 2Δz
So, a2 = 2a1, right ?
 
Try again.
 
BvU said:
Try again.
Hmm..
I tried and got the same answer, a2 = 2a1
Please explain the correct answer to me

EDIT :
Tried again and get a1 = 2a2
 
Last edited:
  • #10
terryds said:
Tried again and get a1 = 2a2
Good.
 
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  • #11
terryds said:
Hmm..
I tried and got the same answer, a2 = 2a1
Please explain the correct answer to me

EDIT :
Tried again and get a1 = 2a2

sr i didnt understand , since S = 1/2 at^2
then if Δx=2Δy .
then ax should be equal 2 ay ?
then a2 = 2a1 ?
 
  • #12
jake jungle said:
sr i didnt understand , since S = 1/2 at^2
That's irrelevant to how the lengths x, y and z relate.
jake jungle said:
then if Δx=2Δy .
It isn't.
What combinations of lengths x, y and z are known to be constant?
 

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