Relative Motion- Airplane/Wind

AI Thread Summary
A jetliner with a cruising speed of 620 mph must account for a 120 mph headwind when flying from San Francisco to Chicago, a distance of 2000 miles each way. The correct approach involves calculating the effective speeds for both legs of the trip: 500 mph against the wind and 740 mph with the wind. The total flight time is approximately 6.7 hours, factoring in the wind's impact on both directions. Participants in the discussion confirm this calculation and emphasize the importance of considering the wind's effect on both legs of the journey. The final consensus is that the total round-trip time is indeed 6.7 hours.
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Homework Statement



A jetliner has a cruising air speed of 620mph relative to the air.

Part B
How long does it take this plane to fly round-trip from San Francisco to Chicago, an east–west flight of 2000 miles each way, if the wind is blowing at 120mph from the west to the east?

Homework Equations


The Attempt at a Solution



I've tried 8 hours.
and 7.225 hours.
 
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Show us your work, or we can't tell where, if anywhere, you went astray.
 
i did

620-120= 500

so that makes 4000/500= 8 hoursfor 1 other

it only affects 1 trip

so 2000/620= 3.225

2000/500= 4

so trip time = 7.225

both answers wrong
 
The wind affects the trip in both directions: it helps in one direction and opposes in the other.
 
620 + 120 one-way = 740
620 - 120 one-way = 500

2000/740 mph = 2.70
2000/500 mph = 4
= 6.7 hoursis that correct
 
hi there, welcome to physicsforums. I'm guessing your assumption is that the wind velocity and cruising velocity 'add up' to get the true speed. Since they don't give you any other information, then this does seem like the right way to do it.

I get a different answer to you though. Remember that since he is doing a two-way flight, that on the way there, the plane is going against the wind, and with the wind on the way back.

EDIT: lol, I only saw your first post when I wrote this. And yes, I also get an answer of 6.7 hours
 
BruceW said:
hi there, welcome to physicsforums. I'm guessing your assumption is that the wind velocity and cruising velocity 'add up' to get the true speed. Since they don't give you any other information, then this does seem like the right way to do it.

I get a different answer to you though. Remember that since he is doing a two-way flight, that on the way there, the plane is going against the wind, and with the wind on the way back.


I posted some new work, is that what you got?
 
yep! nice work :)
 
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