Relative velocity of a ball on a train

AI Thread Summary
The discussion revolves around calculating the velocity of a ball thrown inside a moving train. The train travels at 72.0 km/hr, and the ball is thrown horizontally north, crossing a distance of 1.9 m in 0.75 seconds. The initial calculations yielded a speed of 40 m/s, which was identified as incorrect. It was clarified that the velocity of the train is irrelevant to the boy's perspective, as he and the ball are not moving relative to each other. The key takeaway is that the ball's velocity from the boy's point of view is determined solely by its motion within the train, not the train's speed.
MickeyBlue
Messages
25
Reaction score
2

Homework Statement


A train is traveling east along a straight run of track at 72.0 km/hr. Inside, two siblings 1.9 m apart are playing catch directly across the aisle. The kid wearing a P.J.Harvey T-shirt throws the ball horizontally north. The ball crosses the train and is caught 0.75 s later by her little brother. (Ignore any effects of gravity or friction.) Find the magnitude of the ball's velocity from the little brother's point of view.

Homework Equations


1. xf = xi + ViΔt + 1/2ax(Δt)2
2. a2 = b2 + c2

The Attempt at a Solution


I used the first equation to calculate the velocity of the ball in the y-axis. I assumed that xi = ax = 0 and got 2.5 m/s. I then used Pythagoras and head-to-tail vector addition to get the actual speed and direction of the ball, taking speed in the x-axis as the speed of the train (20m/s). I took the brother to be moving at the same speed and direction as the train. My final answer was 40 m/s.

I know this is the wrong answer but I can't work out why. Any advice?


 
Physics news on Phys.org
What about a simpler question; what is the balls velocity from the boy's point of view before the ball is thrown? Is the ball moving relative to the boy?

The velocity of the train is irrelevant as the boy, girl, and train are not moving relative to each other. Similarly, if they were playing catch at the train station the Earth's motion relative to the sun or the solar systems velocity relative to the centre of the milky way isn't relevant: the velocity the boy sees is relative to himself.
 
billy_joule said:
What about a simpler question; what is the balls velocity from the boy's point of view before the ball is thrown? Is the ball moving relative to the boy?

The velocity of the train is irrelevant as the boy, girl, and train are not moving relative to each other. Similarly, if they were playing catch at the train station the Earth's motion relative to the sun or the solar systems velocity relative to the centre of the milky way isn't relevant: the velocity the boy sees is relative to himself.
That was the way I thought about it at first, which got me my 2.5 m/s. I thought because the boy was "technically" stationary it wouldn't affect the true velocity of the ball.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top