Relative Velocity: How Far Will the Boat Move Downstream Without Correction?

AI Thread Summary
To determine how far the boat moves downstream while crossing a 300 m wide river flowing at 3 m/s, one must calculate the time it takes for the boat to reach the opposite shore. Given the boat's speed of 10 m/s north, it takes 30 seconds to cross. During this time, the river's current pushes the boat downstream at 3 m/s, resulting in a downstream displacement of 90 m. The final answer indicates that the boat will move 90 m downstream by the time it reaches the far shore. Understanding the interplay of velocities is crucial for solving such relative motion problems.
AimlessWander
Messages
15
Reaction score
0

Homework Statement



A river flows with a velocity of 3 m/s east. The river is 300 m wide. A boat is moving 10 m/s due north. If the river flow is not corrected for, how far will the boat have moved downstream by the time is reaches the far shore?

Homework Equations


Trigonometry and kinematic equations


The Attempt at a Solution


90 m?
 
Physics news on Phys.org
Cool - how did you arrive at that figure?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top