Relativistic electrons and positrons

AI Thread Summary
An electron and positron, each with a rest mass energy of 511 keV, collide to create a proton and antiproton with a rest mass energy of 938 MeV. The minimum kinetic energy required for this process is calculated to be 937.5 MeV for each particle. Initial calculations suggested an impossible speed of 60 times the speed of light, prompting a reevaluation. The correct approach involves using the relativistic energy formula, which confirms that the particles would move at 0.9999998 times the speed of light. This highlights the importance of using appropriate relativistic equations in such scenarios.
mangojuice14
Messages
6
Reaction score
0

Homework Statement


The question states that an electron and positron, each with rest mass energy of 511keV collide head on and create a proton and antiproton each with rest mass energy 938MeV. The question asks us to find the minimum kinetic energy of the electron and positron.

Homework Equations


Relativistic energy: E = T + mc2 where T is the kinetic energy.

The Attempt at a Solution


I have solved the problem with the relativistic energy equations by setting the proton's and antiproton's final state at rest
T(electron) +mec2 = mpc2
and obtained the solution that the electron and positron each would need a kinetic energy of 937.5MeV.

I checked the answer and it's correct but the energy implies that the electron would be moving at 60 times light speed. Does this mean the problem is purely theoretically and is not physically possible or am I missing something. Thanks
 
Physics news on Phys.org
mangojuice14 said:
Welcome to PF!

I checked the answer and it's correct but the energy implies that the electron would be moving at 60 times light speed.
Can you show your calculation for this? Remember, the formula for kinetic energy, T, in relativity is not (1/2)mv2.
You should be able to show that an electron with any finite amount of energy (no matter how large) would still move at less than the speed of light.
 
  • Like
Likes mangojuice14
TSny said:
Can you show your calculation for this? Remember, the formula for kinetic energy, T, in relativity is not (1/2)mv2.
You should be able to show that an electron with any finite amount of energy (no matter how large) would still move at less than the speed of light.

Oh right! I was actually using the small velocity approximation...woops. Using $$E = \frac {mc^2} {\sqrt{1-\frac{v^2}{c^2}}}$$ where E would be 938MeV, I now obtain a speed of 0.9999998c. Thanks!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top