- #1

Oijl

- 113

- 0

## Homework Statement

Nevermind, got it.

Two spaceships approach the Earth from opposite directions. According to an observer on the Earth, ship A is moving at a speed of 0.753c and ship B at a speed of 0.851c. What is the speed of ship A as observed from ship B? Of ship B as observed from ship A?

## Homework Equations

v = (v' + u) / (1+ (v'u)/(c^2))

and so

v' = (u - v) / ((vu)/(c^2) - 1)

## The Attempt at a Solution

u is the speed of A as observed from Earth.

v is the speed of B as observed from Earth.

v', then, would be the speed of A or B as observed from the other ship.

The values 0.753c and 0.851c plugged in, I get 0.2728c = v'.

The speed of one ship as observed by the other ship should be greater than either of the ship's speeds as observed on earth. So where am I incorrect?

Last edited: