Relativistic velocity problem with x and y components

Click For Summary
SUMMARY

The discussion focuses on calculating the velocity of Rocket 2 as measured in the reference frame of Rocket 1, with Rocket 1 traveling at 0.6c in the positive y-direction and Rocket 2 at 0.8c in the positive x-direction. The correct calculation for the x-component of Rocket 2's velocity (Ux) is determined to be 0.64c using the relativistic velocity addition formula. The participants also discuss the need to apply Lorentz transformations to derive the y-component (Uy) of Rocket 2's velocity in Rocket 1's frame. The conversation emphasizes the importance of correctly assigning reference frames and using appropriate equations.

PREREQUISITES
  • Understanding of special relativity and relativistic velocity addition
  • Familiarity with Lorentz transformations
  • Knowledge of the speed of light (c) and its implications in physics
  • Basic vector decomposition in two-dimensional motion
NEXT STEPS
  • Study the Lorentz transformation equations in detail
  • Learn about relativistic velocity addition in multiple dimensions
  • Practice problems involving velocities approaching the speed of light
  • Explore the implications of relativistic effects on time and space
USEFUL FOR

Students and educators in physics, particularly those focusing on special relativity, as well as anyone interested in advanced kinematics and relativistic motion analysis.

Luke Cohen
Messages
30
Reaction score
1

Homework Statement


Two rockets leave their space station along perpendicular paths, as measured by a flight controller on the space station (see figure). The flight controller records the speeds of Rockets 1 and 2 to be 0.6 c and 0.8 c respectively. What is the velocity of Rocket 2 as measured in the reference frame of Rocket 1? Give both the components and the magnitude of this velocity

Rocket one is going in the positive y direction and rocket 2 is going in the positive x direction.

Homework Equations


Lorentz2.gif


The Attempt at a Solution



So I tried setting it up by using rocket 1 as the S' frame and rocket 2 as the S frame. The components of velocity are: S' = (-0.8c, 0.6c, 0) and S = (0.8c, -0.6c, 0). Plugging these values into the Ux equation, -0.8 + -0.8 / (1+0.64), but the correct answer is 0.64c for Ux. I also need to figure out Uy, but I think if you can help me solve for Ux, then I can solve for Uy myself. I appreciate all help, Thanks!
 
Physics news on Phys.org
Luke Cohen said:

Homework Statement


Two rockets leave their space station along perpendicular paths, as measured by a flight controller on the space station (see figure). The flight controller records the speeds of Rockets 1 and 2 to be 0.6 c and 0.8 c respectively. What is the velocity of Rocket 2 as measured in the reference frame of Rocket 1? Give both the components and the magnitude of this velocity

Rocket one is going in the positive y direction and rocket 2 is going in the positive x direction.

Homework Equations


Lorentz2.gif


The Attempt at a Solution



So I tried setting it up by using rocket 1 as the S' frame and rocket 2 as the S frame. The components of velocity are: S' = (-0.8c, 0.6c, 0) and S = (0.8c, -0.6c, 0). Plugging these values into the Ux equation, -0.8 + -0.8 / (1+0.64), but the correct answer is 0.64c for Ux. I also need to figure out Uy, but I think if you can help me solve for Ux, then I can solve for Uy myself. I appreciate all help, Thanks!

You can write the Lorentz transformation T1 for (x,y,t) to (x1,y1,t1) with velocity v1 along the x-axis, and the Lorentz transformation T2 for (x,y,t) to (x2,y2,t2) with velocity v2 along the y-axis. To get the transformation for (x1,y1,t1) to (x2,y2,t2), just express express (x2,y2,t2) in terms of (x,y,t) and then express (x,y,t) in terms of (x1,y1,t1). From that, you can work out the relative velocity. However, it will be messy, so get out several sheets of paper and a sharp pencil. Alternatively, you can use a computer algebra system to make it manageable.
 
I don't think my professor would assign anything requiring a computer algebra system... I am also sure that I should be able to solve this problem with the LT equation above for Ux and then the LT equation for Uy. Is there something I am doing incorrectly with my assigning of values to the variables U'x or V?
 
Luke Cohen said:
I don't think my professor would assign anything requiring a computer algebra system... I am also sure that I should be able to solve this problem with the LT equation above for Ux and then the LT equation for Uy. Is there something I am doing incorrectly with my assigning of values to the variables U'x or V?

If (x1,y1,t1) is obtained from (x,y,t) by a Lorentz transformation T1 with velocity v1 along the x-axis, then coordinates of particle 2 (relative to particle 1) are obtained by putting (x,y,t) = (0,v2t,t) in the transformation equation T1. From that you can get the velocities in the 1-frame.
 
Last edited:
Luke Cohen said:

Homework Statement


Two rockets leave their space station along perpendicular paths, as measured by a flight controller on the space station (see figure). The flight controller records the speeds of Rockets 1 and 2 to be 0.6 c and 0.8 c respectively. What is the velocity of Rocket 2 as measured in the reference frame of Rocket 1? Give both the components and the magnitude of this velocity

Rocket one is going in the positive y direction and rocket 2 is going in the positive x direction.

Homework Equations


Lorentz2.gif


The Attempt at a Solution



So I tried setting it up by using rocket 1 as the S' frame and rocket 2 as the S frame. The components of velocity are: S' = (-0.8c, 0.6c, 0) and S = (0.8c, -0.6c, 0).
I don't see how you got those. It's not even clear what frame you're saying these velocities would be observed in. Note that you're also claiming that S and S' are both moving with speed ##c## relative to whatever rest frame you're using since (0.8)^2+(0.6)^2 = 1.

Plugging these values into the Ux equation, -0.8 + -0.8 / (1+0.64), but the correct answer is 0.64c for Ux. I also need to figure out Uy, but I think if you can help me solve for Ux, then I can solve for Uy myself. I appreciate all help, Thanks!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
13
Views
2K
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
5
Views
2K