How Does Relativity Affect Perceptions of Time and Length in Motion?

AI Thread Summary
The discussion focuses on a physics problem involving a racehorse traveling at 0.9c down a 2000m straightaway. It addresses how time and length are perceived differently from the grandstand and the jockey's perspectives, highlighting concepts of time dilation and length contraction. The calculations for the time taken by the horse according to the grandstand and the apparent length from the jockey's viewpoint are discussed, leading to confusion in determining the speed of the horse relative to the grandstand. The conclusion emphasizes that both the grandstand and the jockey agree on their relative speed of 0.9c. The thread seeks clarification on the final calculation, indicating a common challenge in understanding relativity.
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Homework Statement


A race horse can travel down a 2000m straightaway at a speed of 0.9c.

a) How long does it take the horse to run the straightaway according to a timer sitting in the grandstand?
b) From the jockey's perspective, the length of the straightaway appears to be less than 2000 m. What is the apparent length?
c) How long does it take for the horse to run the straightaway according to the jockey?
d) What would the jockey calculate for the speed of the horse relative to the grandstand?


It seems like I'm doing things right until the last part, but I put up my work for the first three parts so you'll know my thought process that leads me to my problem in part d.

Homework Equations





The Attempt at a Solution



a) ∆t = length/speed
Length of the straightaway according to a timer in the grandstand would be 2000m, because there would be no length contraction for the timer.
length=2000m
The speed is given at 0.9c.
speed=0.9c
Therefore,
∆t = 2000/(0.9c) = some value

b)L = Lo[sqrt(1-(u^2)/(c^2))]
Lo = 2000m
u = 0.9c
So,
L = 2000[sqrt(1-0.9^2)] = some other value

c) Again, ∆t = length/speed (but here we'll call it ∆to)
∆to = L/(0.9c), where L is the L of part b

d) ...
Speed is length over time, and the length according to the jockey is L, and the time according to the jockey is ∆to, which was calculated using 0.9c as the speed, so 0.9c would be the speed of the horse.



Anyway, thanks for looking at this, and I'm sure someone can give me a good, quick help that sets me straight because I know this is a simple problem.
 
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Looks good to me. The grandstand sees the horse/jockey moving at speed 0.9c, so the horse/jockey sees the grandstand moving at speed 0.9c. (They agree on each other's relative speed.)
 
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