What are the v_j vectors in Cahn's representation of the Lie algebra of SO(3)?

jdstokes
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Hi all, I asked this on the Quantum Physics board but didn't get a response.

I'm reading Cahn's book on semi-simple lie algebras and their representations.

http://www-physics.lbl.gov/~rncahn/book.html

In chapter 1, he attempts to build a (2j+1)-dimensional representation T of the Lie algebra of SO(3) starting with the abstract commutation relations

[T_z,T_+] = T_+, \quad [T_z,T_-] = - T_-,\quad [T_+,T_-] = 2T_z Eq (I.14).

He begins by defining the action of T_z,T_+ on the vector v_j by

T_z v_j = j v_j, \quad T_+ v_j = 0

but he does not explain what the v_j's are. How does one even know that such vectors exist?

Any help would be greatly appreciated.
 
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jdstokes said:
Hi all, I asked this on the Quantum Physics board but didn't get a response.

I'm reading Cahn's book on semi-simple lie algebras and their representations.

http://www-physics.lbl.gov/~rncahn/book.html

In chapter 1, he attempts to build a (2j+1)-dimensional representation T of the Lie algebra of SO(3) starting with the abstract commutation relations

[T_z,T_+] = T_+, \quad [T_z,T_-] = - T_-,\quad [T_+,T_-] = 2T_z Eq (I.14).

He begins by defining the action of T_z,T_+ on the vector v_j by

T_z v_j = j v_j, \quad T_+ v_j = 0

but he does not explain what the v_j's are. How does one even know that such vectors exist?

Any help would be greatly appreciated.

[EDIT]I've decided to answer on the quantum physics forum[/EDIT]
 
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