Resistance and Temperature(isn't this right?)

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A platinum resistance thermometer shows a resistance of 200 ohms at 0°C and 280 ohms at the melting point of a substance. The temperature coefficient of platinum is 0.00392(°C)−1, leading to the equation 280 = 200 [1 + 0.00392(T - 0)]. The calculated melting point is 102.04°C, which aligns with the results from an online calculator. However, there is uncertainty about significant figures, suggesting the final answer may need to be reported as 102°C. The discussion highlights the importance of precision in calculations and potential oversights in problem-solving.
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Homework Statement



A platinum resistance thermometer has a resistance of 200 when placed in a ice 0◦C
bath and 280 when immersed in a crucible containing a melting substance. What is
the melting point of the substance? The temperature coefficient of the platinum is
0.00392(◦C)−1. Answer in units of ◦C.


Homework Equations



R = r [1 + a(T - t)]

The Attempt at a Solution



This looks like such a simple problem, just plug and chug, but I keep getting the wrong answer.

280 = 200 [1 + 0.00392(T - 0)]
1.4 = 1 + 0.00392T
0.4 = 0.00392T
T = 102.04
 
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Tekmachine said:

Homework Statement



A platinum resistance thermometer has a resistance of 200 when placed in a ice 0◦C
bath and 280 when immersed in a crucible containing a melting substance. What is
the melting point of the substance? The temperature coefficient of the platinum is
0.00392(◦C)−1. Answer in units of ◦C.

Homework Equations



R = r [1 + a(T - t)]

The Attempt at a Solution



This looks like such a simple problem, just plug and chug, but I keep getting the wrong answer.

280 = 200 [1 + 0.00392(T - 0)]
1.4 = 1 + 0.00392T
0.4 = 0.00392T
T = 102.04

The online calculator would seem to agree with your answer:
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/restmp.html#c3
 
LowlyPion said:
The online calculator would seem to agree with your answer:
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/restmp.html#c3
That's the calculator I used ^ ^, hmmmm is there something I'm forgetting to take into account? Maybe some sort of trick to the problem?
 
Tekmachine said:
That's the calculator I used ^ ^, hmmmm is there something I'm forgetting to take into account? Maybe some sort of trick to the problem?

Perhaps the significant figures is in error? They would want only 102 C?
 
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