Resistance of cylinder case a and case b

AI Thread Summary
The discussion focuses on the differences between two cases of wire resistance calculations, specifically case a and case b. Case a involves a straight wire with a given length and a uniform cross-sectional area, while case b involves a coiled wire where the radius is provided, requiring calculations based on the coil's circumference. The importance of the wire's shape, cross-section, and insulation is highlighted, as these factors influence resistance. The participants question how the wrapping of the wire into a coil affects resistance and whether the wire's un-insulated nature and contact between sides are significant. Understanding these distinctions is crucial for accurately applying resistance formulas in different scenarios.
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Homework Statement



what's the difference between case a (photo 1&2) and case b (photo 3 ) ? what can't i use the way of doing case b for case a? p/s : my own working for case a in photo 4

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The Attempt at a Solution

 

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Do you have any reason to think they should be handled differently?
Please show how you are thinking about these problems?
 
for case a , i do it in this way because since the length is already given , I sub l=0.05m (case b provide radius only, so i use 2pi r to find the total length in a coil) , area= uniform cross sectional area, 1.0mm^2
 
or case a , i do it in this way because since the length is already given , I sub l=0.05m
For case (a) the length of the wire is given, not the length of the coil.

If you just put a current down the straight wire, you'd use ##R=\rho L/A## where L is the length of the wire and A is it's cross-sectional area.

But the problem writer is making a big deal out of the fact the wire is not straight and it isn't a regular wire.

i.e. It says the wire has a square cross-section - why is that important?

How would wrapping the wire into a coil make a difference?

Is it important that the wire is un-insulated?

Is it important that the sides of the wire touch each other?
 
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