Resistive dissipation and Ohm's law

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SUMMARY

The discussion focuses on the relationship between voltage (V), current (i), resistance (R), and power (P) in electrical devices, specifically in the context of Ohm's Law. It establishes that doubling the voltage or current results in a quadrupling of power dissipation (P' = 4P). In contrast, doubling the resistance while keeping voltage or current constant does not change the power dissipation, as indicated by the equations P = i²R and P = V²/R. The participants clarify that Ohm's Law is inherently applied in the calculations, and variations in resistance can lead to different configurations of the device.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with electrical power equations (P = i²R and P = V²/R)
  • Basic knowledge of electrical components and their behavior
  • Ability to manipulate and analyze equations
NEXT STEPS
  • Explore the implications of Ohm's Law in circuit design
  • Learn about power dissipation in resistive circuits
  • Investigate the behavior of variable resistors (potentiometers)
  • Study the effects of non-linear components on power calculations
USEFUL FOR

Students studying electrical engineering, educators teaching circuit theory, and professionals involved in electronics design and analysis.

AdrianMachin
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Homework Statement


A potential difference V is connected across a device with resistance R, causing current i through the device. Rank the following variations according to the change in the rate at which electrical energy is converted to thermal energy due to the resistance, greatest change first:
(a) V is doubled with R unchanged,
(b) i is doubled with R unchanged,
(c) R is doubled with V unchanged,
(d) R is doubled with i unchanged.

Homework Equations


$$P= {i^2} R$$
$$P= \frac {V^2} R$$

The Attempt at a Solution


I know and understand that (a) and (b) result in ##P'=4P##, but I'm not sure if I judge (c) and (d) variations correctly. I guess that the answer to (c) and (d) is that there would be no change if the device obeys Ohm's law.
 
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You can assume some values for V and R and check each condition. You have listed the correct equations.
AdrianMachin said:
guess that the answer to (c) and (d) is that there would be no change if the device obeys Ohm's law.
No change in what?
 
cnh1995 said:
You can assume some values for V and R and check each condition. You have listed the correct equations.

No change in what?
No change in ##P##.
 
AdrianMachin said:
No change in ##P##.
There will be changes in P according to the equations you've listed.
 
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cnh1995 said:
There will be changes in P according to the equations you've listed.
I think I was wrong to worry about the Ohm's law, it is actually embedded in those two equations.
 
It looks like they only want you to worry about the changes that each choice asks about. Obviously if R is kept constant (in the first two), then a change in V results in a change in I, as well as a change in I would result in a change in V (per Ohm's Law). So the bottom two tell you that somehow the device has changed (maybe it is a potentiometer, which you can adjust), and they are able to configure the supply to remain constant in the listed variable.
 

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