How do I simplify this resistor circuit for my homework?

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To simplify the resistor circuit, the bottom branch combines to 60 Ohms. The top right resistor is shorted out and can be disregarded. The remaining resistors consist of 30 Ohms in parallel with another 30 Ohms and the combined 60 Ohms from the bottom. The equivalent resistance is calculated using the formula for parallel resistors, resulting in 12 Ohms. This approach clarifies the circuit's simplification process for the homework assignment.
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Homework Statement



Capture2.JPG


Homework Equations



Resistors in Series = R1 + R2 + R3... = Req
Resistors in Parallel = 1/R1 + 1/R2 + 1/R3 ... = 1/Req

The Attempt at a Solution



Studying for a test. This sample exam went pretty well. I am having trouble with 3 out of the 20. I can't figure this one out.

The bottom branch can be combined to be Req = 30 + 30 = 60 Ohms

From there, I can't seem to find a way to combine the rest. I have the answer (B) but I can't collapse the circuit.
 
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The top right resistor is shorted out, so it has no effect. Imagine that it's erased from the diagram.
The center point and point b are the same point.
You have 30 in parallel with 30 in parallel with (30+30).
1/[(1/30) + (1/30) + (1/{30+30})] = 12 ohms.
 
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