Resonate Frequency of Parallel RLC Circuit

1. Apr 17, 2012

p75213

1. The problem statement, all variables and given/known data

Determine the resonant frequency of the circuit in Fig 14.28 (See attached)

2. Relevant equations

$$\begin{array}{l} {\rm{How is }} \to {\omega _0}0.1 - \frac{{2{\omega _0}}}{{4 + 4\omega _0^2}} \\ {\rm{derived from }} \to j{\omega _0}0.1 + \frac{{2 - j{\omega _0}}}{{4 + 4{\omega ^2}}} \\ \end{array}$$

I'm sure this is not difficult but I just can't see it.

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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2. Apr 17, 2012

Staff: Mentor

You consider just the two terms with a "j" in them. I've corrected where you omitted a "2".

3. Apr 17, 2012

p75213

Still can't see it.

4. Apr 17, 2012

Staff: Mentor

One of the terms with a j in it is jω0.1

What is the other term with a j in it?

5. Apr 17, 2012

p75213

The other term is -j2w. I still cant see how this helps.

6. Apr 17, 2012

Staff: Mentor

That's only the numerator; what is its denominator?

7. Apr 17, 2012

p75213

How's this? I new it was simple and the answer was already sitting there. It felt a bit like pulling teeth.

Thanks for that.

$$\begin{array}{l} \begin{array}{*{20}{c}} {{\rm{How is}} \to {\omega _0}0.1 - \frac{{2{\omega _0}}}{{4 + 4\omega _0^2}}} \\ {{\rm{derived from}} \to j\omega 0.1 + \frac{{2 - 2j\omega }}{{4 + 4{\omega ^2}}}} \\ \end{array} \\ {\rm{Answer:}} \\ {\rm{At resonance }}Im(Y){\rm{ = 0:}} \\ j{\omega _0}0.1 - \frac{{j{\omega _0}2}}{{4 + 4\omega _0^2}} = 0 \to j\left( {{\omega _0}0.1 - \frac{{{\omega _0}2}}{{4 + 4\omega _0^2}}} \right) = 0 \\ {\omega _0}0.1 - \frac{{{\omega _0}2}}{{4 + 4\omega _0^2}} = 0 \\ \end{array}$$