Ressistance when current-density is not constant

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Resistance in a wire with varying cross-sectional area and non-constant current density can be analyzed by considering the electric field as a function of position. While traditional resistance calculations assume a constant electric field, the relationship can still hold for differential elements of the wire. By determining the electric field E(x) and integrating it to find the potential drop, one can effectively calculate the resistance despite the non-uniform current density. This approach allows for a qualitative understanding of how varying current density impacts overall resistance. The key takeaway is that resistance can still be derived from the relationship between electric field and current density, even when they are not constant.
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I am trying to figure out how it would effect the ressistance R of a wire with length L and variyng cross-sectional area A(x) if the current density was a fuction of the radius of the wire. That is J = J(r).

I'm having trouble with this when it seems like ressistance is the result of a derivation of ohm's law assuming constant E-field such that E = \frac{J}{\sigma} = \frac{V}{l}, but if E is not constant how can one then relate the ressitance to the current-density J?

A qualitative answer is good enough.
 
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But if E is not constant how can one then relate the resistance to the current-density J?
Resistance is by definition ΔV/i(and this is not Ohm's Law).Even though the electric field is not constant it is a law accurate for differential elements. So if you calculate E(x) function and integrate for the corresponding potential drop you can calculate resistance.
 
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