Calculating Total Energy of Positron and Electron in Quantum Physics Problem

In summary, the total energy of the system, including the electron and positron, is 1.180 MeV. This is calculated by adding the rest energy of the electron, 0.511 MeV, to the sum of the positron's kinetic energy, 0.158 MeV, and its rest energy, also 0.511 MeV. This results in the energy of each photon being 0.590 MeV, as a result of the annihilation.
  • #1
aurao2003
126
0

Homework Statement



Hi
I am new to this forum and offering quantum physics at A level. Can anybody help with the following problem:

The rest energy of an electron is 0.511MeV. A positron created in a cloud chamber has 0.158MeV of kinetic energy. It collides with an electron at rest, creating two photons of equal energies as a result of annihilation.

1. calculate the total energy of the positron and the electron.
2. show that the energy of each photon is .590MeV.

Thanks
Ben

Homework Equations





The Attempt at a Solution

 
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  • #2
Hint: What is the total energy of the positron?
 
  • #3
The total energy should be 0.511 x 2. Since the electrons rest energy is 0.511 any particle colliding with it will have the same energy.
 
  • #4
aurao2003 said:
The total energy should be 0.511 x 2. Since the electrons rest energy is 0.511 any particle colliding with it will have the same energy.
Huh? That does not make any sense to me at all. Why should the energy of any other particle be affected by the rest energy of the electron??
Total energy of the system is simply just the sum of the total energies of the electron and the positron. We know that the total energy of the electron is simply its rest energy, 0.511 MeV. So now all we need to do is get the energy of the positron. What is it?
 
  • #5
The energy of the positron is 0.158MeV. Therefore the total energy of the system is 0.158+0.511=0.669 MeV. However the answer is 1.180 MeV.
 
  • #6
aurao2003 said:
The energy of the positron is 0.158MeV. Therefore the total energy of the system is 0.158+0.511=0.669 MeV. However the answer is 1.180 MeV.
0.158 MeV is the kinetic energy of the positron. The total energy of the positron is the sum of its kinetic and rest energies.
 
  • #7
Fightfish said:
0.158 MeV is the kinetic energy of the positron. The total energy of the positron is the sum of its kinetic and rest energies.


Thats true. But I wonder how they obtained 1.180 MeV. Please explain. Thanks.
 
  • #8
The total energy of system = energy of electron + energy of positron
= 0.511 MeV + (0.511 MeV + 0.158 MeV)
= 1.180 MeV
 
  • #9
Fightfish said:
The total energy of system = energy of electron + energy of positron
= 0.511 MeV + (0.511 MeV + 0.158 MeV)
= 1.180 MeV

Thanks a lot. Have a nice day.

Regards
Ben
 

What is the equation for calculating the total energy of a positron and electron in a quantum physics problem?

The equation for calculating the total energy of a positron and electron in a quantum physics problem is E = mc^2, where E is the total energy, m is the mass of the particle, and c is the speed of light.

How do you determine the mass of a positron and electron in a quantum physics problem?

The mass of a positron and electron can be determined using the mass-energy equivalence equation, E = mc^2. By rearranging the equation, the mass (m) can be calculated as m = E/c^2.

What is the role of the speed of light in calculating the total energy of a positron and electron?

The speed of light (c) plays a crucial role in calculating the total energy of a positron and electron. It is a fundamental constant in the mass-energy equivalence equation, E = mc^2, and determines the relationship between mass and energy.

How does the total energy of a positron and electron differ from their individual energies?

The total energy of a positron and electron is the combined energy of the two particles. It takes into account their rest masses as well as their kinetic energies. On the other hand, the individual energies of the particles only consider their respective rest masses.

What are the units of measurement for total energy in a quantum physics problem?

The units for total energy in a quantum physics problem are typically expressed in joules (J) or electron volts (eV). However, other units such as MeV (mega electron volts) or GeV (giga electron volts) may also be used, depending on the scale of the problem.

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