Resulstant force pendulum equilibrium position

AI Thread Summary
The discussion centers on the dynamics of a pendulum in circular motion, emphasizing that while the pendulum moves in a circular arc, its tangential acceleration is zero at the equilibrium position. The centripetal force, necessary for circular motion, is provided by tension, which exceeds the gravitational force (mg). Participants clarify that even with zero tangential acceleration, there is still centripetal acceleration present. The conversation also touches on the implications of treating the pendulum's motion as simple harmonic motion, noting that this approach simplifies the analysis to one dimension. Understanding these forces is crucial for analyzing pendulum behavior in equilibrium.
binbagsss
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so it continues to move in a circular arc and so must have a resultant centripetal force acting on it which is provided by tension being greater than mg. However at this point its acceleration it's 0.

So is it correct to say that there is no resultant force momentarily, and if this is the case what would be the other force balancing out the centripetal force

Sorry wording isn't too great, thanks a lot !
 
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hi binbagsss! :smile:
binbagsss said:
However at this point its acceleration it's 0.

no, its tangential acceleration is 0 …

it still has v2/r centripetal acceleration :wink:​
 
tiny-tim said:
hi binbagsss! :smile:


no, its tangential acceleration is 0 …

it still has v2/r centripetal acceleration :wink:​

oh right, so going by x proportional to a, so in zero position both are 0.. is this referring to the tangential acceleration?

thanks :)
 
that's right! :smile:

when we treat something as simple harmonic motion we are treating it as one-dimensional, so the rules about maximum acceleration etc only refer to that dimension :wink:
 
ahh thanks a lot :D
 
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