Retrieving exact value using Compound angle

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The discussion centers on the challenge of retrieving exact values using compound angles when the angles involved are not standard special angles. Participants explore methods to express angles like 11π/12 and 175° in terms of known angles. There is confusion regarding the simplification of expressions involving tangent, particularly when dealing with radicals in the denominator. The solution involves multiplying by the conjugate of the denominator to eliminate the radical. Ultimately, the conversation emphasizes the importance of rationalizing denominators in trigonometric expressions.
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Homework Statement


compoundanglehelp.png

Homework Equations


cmpdangleformulae.png

The Attempt at a Solution


I'm stuck. I don't know what to do when the angle cannot be the sum or difference of two special angles (like 45,60,30). I tried taking a look at other topics, but there wasn't a clear solution for me to follow.
 
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For b, try 30° - 45° = -15°

For c, 11\pi/12 = \pi - \pi/12, or 175° = 180° - 15° = 180° + 30° - 45°
 
Ok, you showed me more than one way to get to the required angle. Would all the various ways end up giving me the same answer?
 
How about you try each way and see?
 
If I do 45-60, and 30-45 I get (I used tan(a-b), where 'a' is smaller and 'b' is the larger value)

1 - root of 3
------------ <-- divided by
1 + root of 3

correct answer is:

-2 + root of 3.. <-- no denominator

How do they get that?
 
aeromat said:
If I do 45-60, and 30-45 I get (I used tan(a-b), where 'a' is smaller and 'b' is the larger value)

1 - root of 3
------------ <-- divided by
1 + root of 3

correct answer is:

-2 + root of 3.. <-- no denominator

How do they get that?
Multiply the numerator and denominator by the conjugate of the denominator:
\frac{1 - \sqrt{3}}{1 + \sqrt{3}} \cdot \frac{1 - \sqrt{3}}{1 - \sqrt{3}}=...
It's not considered simplified if you have a rational expression with a radical in the denominator, so that's why we do this.
 
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