Reversible adiabatic expansion proof

AI Thread Summary
The discussion focuses on proving the relationship between pressure (P) and temperature (T) for an ideal gas undergoing reversible adiabatic expansion, expressed as T^(Cp,m/R)/P = constant. Participants explore the application of the first law of thermodynamics and the ideal gas law, with relevant equations including ΔU=Q-W and PVγ= constant. One user struggles with manipulating the equations to isolate temperature in the desired form, initially feeling stuck on how to incorporate the heat capacity ratio (γ). After guidance, they realize that starting from the differential form of internal energy (dU=Cv,m dT=-PdV) is crucial for deriving the relationship. Ultimately, they confirm that integrating this equation leads to the correct proof.
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Homework Statement


Prove the relationship between the pressure, P, and the temperature, T, for an ideal gas with a reversible adiabatic expansion. Base the proof on the first law of thermodynamics and the ideal gas law.

The relationship is: T^(Cp,m/R)/P = constant

Where R is the gas constant and Cp,m is the molar heat capacity.

Homework Equations


ΔU=Q-W
pV=nRT

Possibly relevant:
Wrev=-pdV
γ=Cp,m/Cv,m where γ is the heat capacity ratio.
PVγ= constant

The Attempt at a Solution


I don't even know where to start explaining what I have tried... I have been kicking around a lot of things. I can't seem to manage to manipulate things so that temperature is to the power of anything, although I have burnt a lot of time trying to turn PVγ into some relation for T to the power of some derivative of gamma. I assume since gamma has Cp,m in it, that it is going to play in, and especially since it is already a power for volume, this flagged me in that direction, but I am just going around in circles.

Any help in the right direction would be GREATLY appreciated.
 
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Latsabb said:
The relationship is: T^(Cp,m/R)/P = constant

Where R is the gas constant and Cp,m is the molar heat capacity.

Homework Equations


ΔU=Q-W
pV=nRT

Possibly relevant:
Wrev=-pdV
γ=Cp,m/Cv,m where γ is the heat capacity ratio.
PVγ= constant

The Attempt at a Solution


I don't even know where to start explaining what I have tried... I have been kicking around a lot of things. I can't seem to manage to manipulate things so that temperature is to the power of anything, although I have burnt a lot of time trying to turn PVγ into some relation for T to the power of some derivative of gamma. I assume since gamma has Cp,m in it, that it is going to play in, and especially since it is already a power for volume, this flagged me in that direction, but I am just going around in circles.
Start with PVγ= constant and substitute nRT/P for V.

AM
 
Ok, so I end up with:
P*(nRT/P)γ=c

Which I then turn into:
P*(nRT)γ/Pγ=c

And then:
(nRT)γ/Pγ-1=c

Am I on the right track? Because I have been playing around with it, and I can't seem to extract nR out, nor am I having luck manipulating the powers to what I need.
 
If you are supposed to use the first law, then you are expected to start with

##dU=nCvdT=-PdV##
 
I finally got it nailed down. Chester was correct, the missing piece here was that dU=Cv,mdT=-PdV. An integration of that, and some minor modifying of terms produced what I was after. Thank you!
 
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