Rewriting Complex Trigonometric Expressions: Help Needed

  • Thread starter Thread starter john425
  • Start date Start date
AI Thread Summary
The discussion focuses on rewriting the expression -i arctan(ix) = arctanh(x) + c and specifically on transforming sqrt[(1 + i tan(t)) / (1 - i tan(t))] into the form cos(t) + i sin(t). Participants suggest that rewriting trigonometric functions in terms of sine and cosine can clarify the algebraic manipulations needed. There is an emphasis on ensuring that substitutions are correct to facilitate the conversion. The conversation highlights the importance of understanding the relationships between trigonometric identities and complex numbers in achieving the desired expression. Overall, the thread seeks algebraic assistance for these complex transformations.
john425
Messages
21
Reaction score
0
I am trying to rewrite -i arctan ix = arctanh x + c as
e^it = cos t + i sin t

I am having trouble rewriting
sqrt[ 1 + i tan t / 1 - i tan t]

as
cos t + i sin t

Is this possible or did I do something wrong?
What do I multiply the sqrts by.
 
Physics news on Phys.org
When one is lost, it often helps to rewrite all trig functions in terms of sine and cosine.
 
How does that help here?
 
I just need help with the algebra, if my substitutions are correct
 
Because it usually helps you see the necessary manipulations. Besides, the answer you seek is in terms of sines and cosines, so you'll have to do it sometime anyways.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top