What is the solution to the rifle momentum problem?

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The discussion centers on solving a physics problem involving the conservation of momentum related to a rifle firing a bullet. The user correctly identifies that the momentum of the rifle must equal the momentum of the bullet but in the opposite direction. They calculate the recoil speed of the rifle to be -0.5 m/s, assuming the bullet's momentum is 5.0g times 300 m/s. For the second part, they suggest combining the masses of the rifle and the man to find the recoil speed of both together. The conversation highlights the application of momentum conservation principles in understanding recoil dynamics.
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Homework Statement


A rifle with a weight of 30N fires a 5.0g bullet with a speed of 300 m/s

(a) Find the recoil speed of the rifle

(b) If a 700 N man holds the rifle firmly against his shoulder, find the recoil speed of the man and the rifle



Homework Equations


i think this problem has something to do with the conservation of momentum equation but i am not sure



The Attempt at a Solution


I have no idea how to even begin this problem
 
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Momentum of the bullet is 5.0g times 300 m/s, right? So the momentum of the riffle is the same but in the opposite direction. What is the mass of the rifle given that the weight of the rifle is 30 N? Momentum of the rifle is the mass of the rifle times its velocity...
 
Total velocity before firing = 0...Momentum of the rifle must be equal but opposite to that of the bullet, ie. (0.005kg*300m/s)+(3kg*v)=0, and v= -0.5m/s... I ain so sure bout tha second part, but I think you'll just combine the masses of the rifle and the man (70kg), and find the v in the same way...can anyone correct me if I'm wrong? We're just starting this topic...
 
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