How can I derive the quality factor in an RLC circuit?

AI Thread Summary
The quality factor (Q) in an RLC circuit can be derived using the formula Q = Lω₀/R, where ω₀ is the resonant frequency. The relationship Q = ω₀/Δω is also valid, with Δω defined as R/L. The peak energy stored in the circuit is given by LI²/2, while the power dissipated is I²R/2. The time period of one cycle can be expressed as 2π/ω, leading to the final expression for Q. This derivation specifically applies to series LCR circuits, with a different expression for parallel circuits.
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I need some help deriving the quality factor in an rcl circuit
Q=Lw(sub 0)/R. So far I know that Q=w(sub 0)/delta but my professor used this formula to continue the derivation delta w=R/L and I don't know where it comes from. Can anyone give me a hint?
 
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Quality factor is defined by
Q= 2*pi*(energy stored in resonator)/(energy lost per cycle).

The peak stored energy is LI^2 / 2.

The power dissipated in the resistance is I^2R/2, in terms of the peak current.
The time in one cycle is 1/f or, in terms of angular frequency, 2\pi/\omega. Putting these into the definition of quality factor gives
Q=\frac{\omega L}{R}.

EDIT: clean up equation rendering and add following:
Note that this is true for a series LCR circuit. For a parallel circuit Q is one over the expression on the right!
 
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thanks a lot
 
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