Rock whirling in vertical circle

AI Thread Summary
To achieve tangential and radial acceleration equality for a rock whirling in a vertical circle at a 37-degree angle, the required speed can be derived from the equation v² = gr.sin(θ), where g is the acceleration due to gravity (9.8 m/s²) and r is the radius (8 m). The discussion emphasizes the relationship between weight (W), mass (m), and acceleration in the context of circular motion. The equation Wsin(θ) = ma is referenced to establish the connection between forces acting on the rock. Ultimately, the calculations confirm that the speed must satisfy the derived formula for the specific angle. Understanding these dynamics is crucial for analyzing circular motion in physics.
nrc_8706
Messages
69
Reaction score
0
a rock whirls in a vertical circle of radius 8m. acceleration of gravity 9.8m/s^2

what must the speed be to have tangential=radial acceleration when the string makes a 37 angle with respect to the vertical?

is it Wsinangel=ma

v=Wsinangle*r/m)^1/2 ?
 
Physics news on Phys.org
If W is mg, then yes.

v² = gr.sin@
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top