Rolling without slipping and coefficient of friction

AI Thread Summary
A hollow spherical shell with a mass of 2.50 kg rolls down a 33.0-degree slope, and the minimum coefficient of friction (μ) needed to prevent slipping is determined by equating the force of friction to μ times the normal force. The calculated force of friction is 5.34 N, leading to the equation 5.34 = μmgcos(Θ). The discussion clarifies that the minimum coefficient of friction is derived from the equilibrium of forces acting on the sphere, where static friction prevents slipping. It emphasizes that the coefficient is a function of the slope angle rather than the mass or specific forces involved. The calculation should be verified, as discrepancies in force values were noted.
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Homework Statement


A hollow spherical shell with mass 2.50kg rolls without slipping down a slope that makes an angle of 33.0 with the horizontal.
Find the minimum coefficient of friction μ needed to prevent the spherical shell from slipping as it rolls down the slope.

Homework Equations

The Attempt at a Solution


I already found force of friction = 5.34N.

It seems that I can get the minimum by setting force of friction = μN
So:
5.34 = μmgcos(Θ)

What I don't understand is why this is the minimum of coefficient of friction. How can one assume that this value is the minimum coefficient of friction to prevent slipping?
 
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henry3369 said:

Homework Statement


A hollow spherical shell with mass 2.50kg rolls without slipping down a slope that makes an angle of 33.0 with the horizontal.
Find the minimum coefficient of friction μ needed to prevent the spherical shell from slipping as it rolls down the slope.

Homework Equations

The Attempt at a Solution


I already found force of friction = 5.34N.

How did you get that value?

henry3369 said:
It seems that I can get the minimum by setting force of friction = μN
So:
5.34 = μmgcos(Θ)

What I don't understand is why this is the minimum of coefficient of friction. How can one assume that this value is the minimum coefficient of friction to prevent slipping?
During rolling, it is the force of static friction that prevents slipping, (relative motion of the surfaces in contact). The static friction is not a defined value. It has an upper limit μN: F(static) ≤ μN.
 
You get the minimun coefficient at the equilibrium of two forces: one which accelerates the sphere down the plane with a reduct acceleration, the other which exists only as rection to the first, that is the friction force.
So first calculate the force with "reducted" g and then let it equal to the friction force.
I can anticipate you that when you'll simplified the two member of the equation to obtain the result, you will discovered that the coefficient is function only of the angle and not of the mass or the forces.
The minimun means only that it is enough to keep the mass motionless, and then the force that accelerate it should be greater of the friction force.
Verify the calculate: I obtain for the force a different value...
 
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