Rotating a line anticlockwise about P

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Homework Statement


Find the resulting equation of the line ax+by=c after rotating it anticlockwise by theta degrees about the point P(x0,y0) using the applications of the rotation matrix.


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The Attempt at a Solution

 
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you should be able to multiply it by a rotation matrix. Do you know what this is?
 
not really.. i need the equation of the new line though. I'm not quite sure how to go about this.. please help?
 
you need to translate the line so that its origin is at (x0, y0) then rotate and then translate the line back. You should be able to multiply these different matrices to obtain one matrix. Does this make sense?

I think you should look up matrix transformations if you still don't understand.
 
oh okay thank you. do you have know of a site at all that i may be able to refer to for extra help ?
 
http://wally.cs.iupui.edu/n351/3D/matrix.html

hope it helps
 
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Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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