Rotating particle (complex numbers)

AI Thread Summary
Rotating the line through the origin and point z by 90° results in the line through the origin and point iz, demonstrating a fundamental property of complex numbers. The displacement of a particle is represented as z = ae^(iωt), indicating it moves in a circular path with radius a. The particle's velocity is derived as v = aω, while its acceleration, directed towards the center, is calculated as v²/a. The discussion emphasizes the importance of understanding complex number rotations and their implications in physics. Overall, the thread explores the relationship between complex numbers and circular motion dynamics.
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This problem is from Boas Mathermatical Methods 3ed. Section 16, problem 1.

Show that if the line through the origin and the point z is rotated 90° about the origin, it becomes the line through the origin and the point iz.

Use this idea in the following problem: Let z = ae^iωt be the displacement of a particle from the origin at time t. Show that the particle travels in a circle of radius a at velocity v = aω and with acceleration v^2 / a directed towards the centre of the circle.

The Attempt at a Solution



I can show the first part: adding \pi / 2 to the argument of z gives ae^{i\theta}e^{\pi / 2} which is just iz.

I'm not sure how to set up the second part of the problem, though. How exactly should I use this result?

Thanks
 
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In the problem, the displacement vector is represented by the complex number z=aeiωt. What is the distance of the point from the origin?
You can also show, that adding iθ to the argument of a complex number z, it gets rotated by the angle θ.
The velocity is the time derivative of the displacement. What is dz/dt in this case? What is the magnitude of the velocity?
The acceleration is the time derivative of velocity, second derivative of displacement. What is its magnitude? What is its direction?

ehild
 
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