Rotational Dynamics Homework: 2 Rings M & 4M

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The discussion revolves around a physics homework problem involving two rings of different masses, where the larger ring rotates freely after being released. The key points include the need to conserve linear momentum and the potential energy conversion into kinetic energy as the larger ring reaches a vertical position. There is confusion regarding whether to consider only translational kinetic energy or both translational and rotational kinetic energy for the larger ring. The consensus suggests that both forms of kinetic energy must be accounted for to properly apply conservation laws. The final answer for the angular velocity is given as (20g/17R)^(1/2), but participants express difficulty in deriving this result.
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Homework Statement


Two rings of masses 'm' (smaller one) and '4m' (bigger one) are placed in the set up as shown in the diagram. The smaller ring is hung through a horizontal frictionless thread. The bigger ring is joined to the smaller ring in such a way that it can rotate freely about the point of suspension. The planes of both the rings are perpendicular to the plane of the paper. The bigger ring has a radius 'R'. After the bigger ring is released from the initial position as shown in the figure, find the angular velocity of the bigger ring when its plane becomes vertical i.e the planes of both the rings become vertical.


Homework Equations





The Attempt at a Solution



First of all, when the rings reach the final position, we can calculate the relation between the velocities of the center of masses of both the rings (their velocity vectors will be horizontal and since there is no ext. force in the horizontal direction we can conserve the linear momentum). Now when the bigger ring reaches the final position the decrease in the potential energy of the system is, (4m)gR, which will be converted into kinetic energies of the bodies. But i have a doubt; the K.Es of the smaller ring will be only its linear K.E, but for the bigger ring, what will be the K.E? Will it just the linear K.E of the COM of the ring at that instant? or it will be the rotational energy about the point of suspension? or both?

The answer to the question is (20g/17R)^(1/2), but in no ways i am getting to it.
Please help!
 

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Good question. I think that there will be rotational + tranlational kinetic energy of the bigger ring.
Tranlational kinetic energy of to COM if not there, will violate the conservation of angular momentum.
 
First, About which point are you thinking to conserve angular momentum, because there will always be an external torque at the COM of the bigger ring, which will rotate it about the point of suspension?
Second, why will you consider the translational K.E of the ring, if you already consider the whole K.E of the body (in the form of the rotational KE) about the point of suspension?

Please try to find out the answer, it matches neither ways!
 
Is there anyone??
Plz. help, i am having a terrible time, understanding the problem!
 
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