Rotational Energy of a baseball

AI Thread Summary
To find the fraction of kinetic energy that is rotational for a 250 g baseball pitched at 35 m/s and spinning at 55 rad/s, the formula K_rot = (1/2)Iω² is used to calculate the rotational kinetic energy. The moment of inertia I for a uniform solid sphere is I = (2/5)mr², where m is the mass and r is the radius. The total kinetic energy is calculated using K_tot = (1/2)mv². The fraction of rotational kinetic energy to total kinetic energy is then expressed as K_rot/K_tot. This calculation provides insight into the distribution of energy in the baseball's motion.
Lance WIlliam
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A 250 g baseball is pitched at 35 m/s, and it's spinning at 55rad/s .

What fraction of its kinetic energy is rotational? Treat the baseball as a uniform solid sphere of radius 3.8 cm.


Answer in K_rot_/K_tot


What the?! I am pretty lost on this one...

Do I use K_rot_=(1/2)I\omega^2
 
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Lance WIlliam said:
Do I use K_rot_=(1/2)I\omega^2

Yes this will give the rotational ke of the ball.
 
What is the Fraction of KE though?
 
The total energy of the ball is \frac{1}{2}mv^2
 
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