Rotational Kinematics of a Computer Disk

AI Thread Summary
A computer disk drive starts from rest and has a constant angular acceleration, taking 0.410 seconds to complete its second revolution. To find the time for the first revolution and the angular acceleration, rotational kinematics equations are necessary. The key equation to use is θ = ω₀t + 0.5αt², where ω₀ is the initial angular velocity and α is the angular acceleration. Since the disk starts from rest, the initial angular velocity is zero, simplifying the calculations. Understanding and applying these equations will help determine both the time for the first revolution and the angular acceleration.
Superfluous
Messages
11
Reaction score
1
A computer disk drive is turned on starting from rest and has constant angular acceleration.

If it took 0.410 s for the drive to make its second complete revolution, how long did it take to make the first complete revolution? What is its angular acceleration, in rad/s^2


I cannot find out how to determine the time it takes to complete the first revolution or the angular acceleration at all. Every rotational kinematics equation involves angular velocity, which is not given (except for the fact that it starts from rest).

I do not know how to go about this or which of the exact kinematic equations to use. Any help would be appreciated.
 
Physics news on Phys.org
I've spent several hours on this plugging in and manipulating the rotational kinematics equations but I still cannot figure out what to do. I'm sure it's something extremely obvious, but I can't seem to figure it out. So... any hint at all would be nice. Thanks.
 
Work on finding the angular acceleration first. We know that the angular acceleration is constant, so we can use the equations for rotational kinematics. You'll probably want to use \theta = \omega_0 t + .5 \alpha t^2.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top