A 2.4 kg cylinder (radius = 0.09 m, length = 0.50 m) is released from rest at the top of a ramp and allowed to roll without slipping. The ramp is 0.74 m high and 5.0 m long. What is its rotational kinetic energy?(adsbygoogle = window.adsbygoogle || []).push({});

I just wanted to make sure that I was on the right track...

I=2/5 mr^2

KE=1/2 mv^2 + 1/5 mv^2

Using conservation of energy: mgh=1/2 mv^2 + 1/5 mv^2 and then solve for v and plug into equation for KE.

Does this sound like I'm doing this correctly?

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# Homework Help: Rotational Kinetic Energy

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