1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rotational Motion of a shaft

  1. Oct 29, 2009 #1
    1. The problem statement, all variables and given/known data
    A shaft is turning at 73.8 rad/s at time zero. Thereafter, its angular acceleration is given by
    a = -10.1 rad/s2 - 4.44 t rad/s3.
    where t is the elapsed time. Calculate its angular speed at t = 2.58 s

    2. Relevant equations
    1/2(Angular accel formula)+ 73.8t+0= theta final


    3. The attempt at a solution
    do i take the integral of the accel formula then the velocity the plug in 2.58?
     
  2. jcsd
  3. Oct 29, 2009 #2

    kuruman

    User Avatar
    Homework Helper
    Gold Member

    You need to integrate both sides of

    dω = αdt

    The limits of integration should be

    73.8 to ω (left side) and 0 to 2.58 (right side)

    After you integrate, solve for ω.
     
  4. Oct 29, 2009 #3
    so i set 1/2(angular accel)= 73.8+ theta final? then take the integral?
     
  5. Oct 29, 2009 #4

    kuruman

    User Avatar
    Homework Helper
    Gold Member

    I never said that. I have no idea where you get that 1/2(angular accel) = 73.8 + theta final means something when it is not even dimensionally correct. Do the following integral and solve for ω. That's what I suggested in the first place.

    [tex]\int_{73.8}^{\omega}d \omega=\int_{0}^{2.58}(-10.1-4.44 t) dt[/tex]
     
  6. Oct 29, 2009 #5
    whoa dude calm down. i appericiate the help but remember i was just asking a question, i already feel stupid enough as it is
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Rotational Motion of a shaft
  1. Rotational Motion (Replies: 5)

  2. Rotational Motion (Replies: 2)

  3. Rotational motion (Replies: 8)

Loading...