Rotational Motion Speed at the top of the loop

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SUMMARY

The discussion centers on calculating the speed of a motorcycle at the top of a vertical loop with a radius of 12 meters, where the normal force on the driver is one-fourth of his weight. The correct speed at the top of the loop is definitively established as 9.4 m/s, corresponding to option c. The relevant equations utilized include F=ma, W=mg, T=F-W, and a=v²/r, which are essential for solving problems related to rotational motion and forces.

PREREQUISITES
  • Understanding of Newton's laws of motion (F=ma)
  • Knowledge of gravitational force (W=mg)
  • Familiarity with centripetal acceleration (a=v²/r)
  • Basic principles of forces acting on objects in circular motion
NEXT STEPS
  • Study the derivation of centripetal force in circular motion
  • Explore the effects of varying radius on speed in vertical loops
  • Learn about the role of normal force in circular motion dynamics
  • Investigate real-world applications of rotational motion in vehicles
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of rotational motion and forces acting on objects in circular paths.

physgrl
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Homework Statement



12. A motorcycle travels around a vertical 12 m radius loop. What is its speed at the top of the loop if the normal force exerted by the seat on the driver is equal to ¼ of his weight?

a. 7 m/s

b. 8.1 m/s

*c. 9.4 m/s

d. 15 m/s

e. 88 m/s

Homework Equations



F=ma
W=mg
T=F-W
a=v2/r

The Attempt at a Solution



I did (1/4)W=m(v2/r)-W and I got 12.1 m/s
 
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I get the same answer as you.
 

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