Rotations in Quantum Mechanics Question

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AdamBourke
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Homework Statement





This is more maths than QM I think, but it's at the beginning of my Quantum Questions. Basically, it's about rotations preserving length:

xi is the ith component of a vector, and the length of a vector is determined by the metric ηij according to the equation:

l2 = ηij xixj

where Einstein Summation Convention is used

The action of a geometrical transformation R acting on the vectors can be written:

x' i = R ij x j


Show that R is an isometry (i.e distances are preserved by rotations) if and only if:

R Tη R = η




Homework Equations



None, other than the ones in the question. Unless I'm wrong, which would explain why I can't do the question...

The Attempt at a Solution



Well, I'm not entirely sure where to begin.

I started with the condition:

l2 = ηij xixj = (R Tηij R) R ia x aR jb x b


But then I wasn't really sure a) if the ηij should be encased by the Rs, and b) what do do after that. I tried to write (R Tηij R) as RpiηpqRjq, but that gives an awful lot of Rs and indices which I just can't see how to get rid of:

ηij xixj = RpiηpqRjq R ia x aR jb x b


Am I looking at this completely wrong, or just not seeing something simple? It's an assignment, so I don't want the answer, but I need some help I think.

Thanks,
Adam
 
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If distances are preserved, then the length of [tex]{x'}^i = {R^i}_j x^j[/tex] must be equal to the length of [tex]x^i[/tex]. So it must be that

[tex]\eta_{ij}{x'}^i{x'}^j = \eta_{ij}x^i x^j.[/tex]

You therefore want to determine the condition on [tex]{R^i}_j[/tex] so that this is true.

The approach you took would have worked too, but you would have had to be much more careful about all of the indices in the expression, as well as knowing a property of the inverse of the matrix [tex]R[/tex].