Runner A & B Race: Find Out When & How Far!

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Runner A starts running at 3:00 P.M. with a speed of 3.0 m/s, while Runner B begins 5 minutes later at a speed of 4.0 m/s. To determine when Runner B catches Runner A, the equations for their distances can be set equal: x_A = 3t and x_B = 4(t - 300). Solving for t reveals that Runner B catches Runner A at a specific time, which can be calculated from their speeds and starting times. The distance they run until B catches A can also be calculated using these equations. This problem illustrates the application of relative speed and time in motion scenarios.
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Help with homework??

Runner A, who runs with an average speed of 3.0 m/s, starts out at 3:00 P.M. Runner B, who runs with an average speed of 4.0 m/s, starts after A from the same place exactly 5 min later.
a.) At what time will runner B catch up with runner A?
b.) If the runners stop when B catches A, how far do they run?
 
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this should go in the homework section... as well... you should show some work first, otherwise ppl are not going to help you.
 
phywhat said:
Runner A, who runs with an average speed of 3.0 m/s, starts out at 3:00 P.M. Runner B, who runs with an average speed of 4.0 m/s, starts after A from the same place exactly 5 min later.
a.) At what time will runner B catch up with runner A?
b.) If the runners stop when B catches A, how far do they run?
You know v_A = 3 and v_B = 4 Integrating with respect to time gives x_A = 3t + C_A and x_B = 4t + C_B. When t=0, x_A = 0 so x_A = 3t. When t=300, x_B = 0, so x_B = 4t - 1200. Runner B catches runner A when x_A=x_B. That should be all you need to know.
 
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