- #1
PFStudent
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Title: Scalar form of Coulomb's Law?
Coulomb's Law
Vector Form:
[tex]
\vec{F}_{12} = {\frac{{{k}_{e}}{{q}_{1}}{{q}_{2}}}{{r}^{2}}{\hat{r}_{21}}}
[/tex]
Magnitude Form:
[tex]
|\vec{F}_{12}| = {\frac{{{k}_{e}}{\left|{q}_{1}\right|}{\left|{q}_{2}\right|}}{{r}^{2}}}
[/tex]
So, what is the scalar form of Coulomb's Law?
In addition, when is the scalar form of Coulomb's Law negative?
[tex]
{F}_{12} = {\pm}{\frac{{{k}_{e}}{\left|{q}_{1}\right|}{\left|{q}_{2}\right|}}{{r}^{2}}}
[/tex]
Where: [itex]+[/itex] if [itex]{{q}_{1}}{{q}_{2}} \geq 0[/itex] and [itex]-[/itex] if [itex]{{q}_{1}}{{q}_{2}} < 0[/itex]
I thought it was the above, but I do not believe that is right.
Any help is appreciated.
Thanks,
-PFStudent
Homework Statement
Homework Equations
Coulomb's Law
Vector Form:
[tex]
\vec{F}_{12} = {\frac{{{k}_{e}}{{q}_{1}}{{q}_{2}}}{{r}^{2}}{\hat{r}_{21}}}
[/tex]
Magnitude Form:
[tex]
|\vec{F}_{12}| = {\frac{{{k}_{e}}{\left|{q}_{1}\right|}{\left|{q}_{2}\right|}}{{r}^{2}}}
[/tex]
So, what is the scalar form of Coulomb's Law?
In addition, when is the scalar form of Coulomb's Law negative?
The Attempt at a Solution
[tex]
{F}_{12} = {\pm}{\frac{{{k}_{e}}{\left|{q}_{1}\right|}{\left|{q}_{2}\right|}}{{r}^{2}}}
[/tex]
Where: [itex]+[/itex] if [itex]{{q}_{1}}{{q}_{2}} \geq 0[/itex] and [itex]-[/itex] if [itex]{{q}_{1}}{{q}_{2}} < 0[/itex]
I thought it was the above, but I do not believe that is right.
Any help is appreciated.
Thanks,
-PFStudent