Second order differential equation

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SUMMARY

The discussion focuses on solving the second-order differential equation (d²y/dx²) + (dy/dx) = e^(-x). The characteristic equation m² + m = 0 yields roots m = -1 and m = 0. The user attempts to find a particular integral using the form y = ke^(-x) but encounters a problem when simplifying, leading to k - k = 0 instead of the expected result. A suggested solution is to try the form y = axe^(-x) + be^(-x) for a more accurate particular integral.

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  • Understanding of second-order differential equations
  • Familiarity with characteristic equations and their roots
  • Knowledge of particular integrals in differential equations
  • Basic calculus, including differentiation and integration
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  • Learn about the method of undetermined coefficients for particular integrals
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Students and professionals in mathematics, engineering, and physics who are dealing with differential equations, particularly those seeking to solve second-order linear equations effectively.

mr bob
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I just came across this one, was going really well until i came across this one.

(d^2y/dx^2) + (dy/dx) = e^(-x)
m^2 + m = 0
m = -1 and m = 0

Now i get the particular integral
Try y = ke^(-x)
(dy/dx) = -ke^(-k)
(d^2y/dx^2) = ke^(-x)


ke^(-x) - ke^(-x) = e^(-x)

I get stuck here as k-k= 0, not one.

Any help would be greatly appreciated.
 
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mr bob said:
I just came across this one, was going really well until i came across this one.

(d^2y/dx^2) + (dy/dx) = e^(-x)
m^2 + m = 0
m = -1 and m = 0

Now i get the particular integral
Try y = ke^(-x)
(dy/dx) = -ke^(-k)
(d^2y/dx^2) = ke^(-x)ke^(-x) - ke^(-x) = e^(-x)

I get stuck here as k-k= 0, not one.

Any help would be greatly appreciated.

Try [tex]y=axe^{-x} +be^{-x}[/tex]

-Dan
 
Last edited:

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