Second order differential equation

realmm
Messages
1
Reaction score
0
How do i solve the following equation?

u= L*(d^2i/dt)+ (1/c)*i r* (di/dt)L= 1,4 mF
C= 0,31 H
R= 1000 ohm

Well i have so far found the auxiliary equation:
0,31*r^2 + 1000*r + 1/(1,4*10^-6)=0

And the discriminant is found to be 114286. This makes the form of the solution:

Y=c1*e^r1x + c2*e^r2x

I have found the roots:

r1=-1067,64
r2= -2158,18

But I am stuck now and do not know what to do now.
 
Last edited:
Physics news on Phys.org
Welcome to PF.

Please, show your own work.

For further information, please see the forum guidelines: https://www.physicsforums.com/showthread.php?t=94383
 
Are you sure you have written the equation correctly? As written, it is not a constant coefficient equation and your "auxiliary equation" doesn't make sense.
 
realmm said:
How do i solve the following equation?

u= L*(d^2i/dt)+ (1/c)*i r* (di/dt)
You mean u= l(d^2i/dt^2)+ (1/c)i+ r(di/dt)


L= 1,4 mF
C= 0,31 H
R= 1000 ohm

Well i have so far found the auxiliary equation:
0,31*r^2 + 1000*r + 1/(1,4*10^-6)=0
No, the auxiliary equation would be 1,4r^2+ 1000 di/dt+ 3.2= 0. You are mixing up L and C.

And the discriminant is found to be 114286. This makes the form of the solution:

Y=c1*e^r1x + c2*e^r2x

I have found the roots:

r1=-1067,64
r2= -2158,18

But I am stuck now and do not know what to do now.
What is u? A constant? If so, try a solution of the form i= A, a constant. What would A have to be to satisfy that equation?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top