Second order partial derivatives

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Homework Statement



if z= f(x) + yg(x), what can you say about zyy explain?

Homework Equations





The Attempt at a Solution


z= f(x,yy)
zyy = d/dy (dz/dy) d(partial derivative)
 
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z = f(x,yy) this not correct, i am not sure what it means

try taking the partial derivative and see what you get

remember for partials, the other variable is kept constant during the differentiation, in this case x
 
Consider that d/dx (a(x,y) + b(x,y)) = d/dx a(x,y) + d/dx b(x,y).

Also recall that d/dx (a(x,y)*b(x,y)) = (d/dx a(x,y))*b(x,y) + a(x,y)*(d/dx b(x,y)).
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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