Second order partial derivatives

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SUMMARY

The discussion focuses on calculating the second order partial derivative zyy for the function z = f(x) + yg(x). Participants emphasize the importance of treating other variables as constants during differentiation. The correct approach involves applying the product rule and the sum rule for partial derivatives, specifically noting that d/dx (a(x,y) + b(x,y)) equals d/dx a(x,y) + d/dx b(x,y) and d/dx (a(x,y)*b(x,y)) equals (d/dx a(x,y))*b(x,y) + a(x,y)*(d/dx b(x,y)). This foundational understanding is crucial for accurately computing zyy.

PREREQUISITES
  • Understanding of partial derivatives
  • Familiarity with the product rule and sum rule in calculus
  • Knowledge of functions of multiple variables
  • Basic differentiation techniques
NEXT STEPS
  • Study the concept of higher order partial derivatives
  • Learn about the implications of mixed partial derivatives
  • Explore applications of partial derivatives in multivariable calculus
  • Review examples of differentiating functions of multiple variables
USEFUL FOR

Students studying multivariable calculus, mathematicians focusing on differential equations, and anyone interested in advanced calculus concepts.

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Homework Statement



if z= f(x) + yg(x), what can you say about zyy explain?

Homework Equations





The Attempt at a Solution


z= f(x,yy)
zyy = d/dy (dz/dy) d(partial derivative)
 
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z = f(x,yy) this not correct, i am not sure what it means

try taking the partial derivative and see what you get

remember for partials, the other variable is kept constant during the differentiation, in this case x
 
Consider that d/dx (a(x,y) + b(x,y)) = d/dx a(x,y) + d/dx b(x,y).

Also recall that d/dx (a(x,y)*b(x,y)) = (d/dx a(x,y))*b(x,y) + a(x,y)*(d/dx b(x,y)).
 

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