Semantics question about this angular momentum problem

AI Thread Summary
The discussion revolves around calculating the angular momentum of an airplane relative to a wheat farmer on the ground. The initial calculation yields an angular momentum of -9.03 x 10^9 kg x m^2/s, which is correct. The key point is that while the distance between the farmer and the plane increases, the effective distance used in the angular momentum formula, r*sin(Θ), remains constant due to the altitude of the plane. Thus, even as the plane moves west, the angular momentum remains unchanged because the angle θ adjusts accordingly. The confusion arises from interpreting the relationship between the plane's motion and the farmer's position, but the physics confirms that angular momentum is constant in this scenario.
FisherDude
Messages
23
Reaction score
0

Homework Statement


Heading straight toward the summit of Pikes Peak, an airplane of mass 12,000 kg flies over the plains of Kansas at nearly constant altitude 4.30 km with constant velocity 175 m/s west. a) What is the airplane's vector angular momentum relative to a wheat farmer on the ground directly below the airplane? b) Does this value change as the airplane continues its motion along a straight line?


Homework Equations



mag. of angular momentum = position*mass*velocity*angle between



The Attempt at a Solution



The answer to part a) is (-9.03 x 10^9 kg x m^2/s) j, which I have no problem with. But the answer to part b) is "No, L = |r||p|sin(Θ) = mv(rsinΘ), and r*sinΘ is the altitude of the plane. Therefore, L = constant as the plane moves in level flight with constant velocity."

But the problem asks for the plane's angular momentum relative to the wheat farmer. So if the plane keeps on moving west, wouldn't r (the distance between the farmer and the plane) keep on increasing?

The only way the answer makes sense to me is if they're really asking for the angular momentum of the plane relative to the ground, not the wheat farmer, because then, the distance between the plane and the ground would be constant.

Any help would be great...
 
Last edited:
Physics news on Phys.org
FisherDude said:
But the problem asks for the plane's angular momentum relative to the wheat farmer. So if the plane keeps on moving west, wouldn't r (the distance between the farmer and the plane) keep on increasing?
Sure, the distance r from farmer to plane increases. But r*sinΘ does not. Angular momentum is not just mv*r, but mvr*sinΘ. (Only when the plane is directly overhead does sinΘ = 1.)

The only way the answer makes sense to me is if they're really asking for the angular momentum of the plane relative to the ground, not the wheat farmer, because then, the distance between the plane and the ground would be constant.
Note that r*sinΘ is the distance between plane and ground.
 
You're correct, L remains constant even with the farmer. You realized that r*sin(theta) is simply the altitute, which is constant. You're correct that r will increase because the plane-farmer distance increases. However, sin(theta) will decrease at such a rate to keep L constant. Remember what the angle theta is defined as. It's the angle between the vector r and the vector v. You were allowed to ignore this in your origional calculation because theta = 90 Sin(theta) = 1
 
Wow, I wish i had caught that.

Thanks!
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Replies
17
Views
411
Replies
1
Views
1K
Replies
4
Views
1K
Replies
1
Views
2K
Replies
2
Views
2K
Replies
19
Views
2K
Replies
7
Views
2K
Back
Top