When two springs with different spring constants are arranged in series, the force applied to each spring is the same, represented by F = k1Δl1 for the first spring and F = k2Δl2 for the second. The total force is not equal to the sum of the spring constants multiplied by the total distance stretched. Instead, the equivalent spring constant for springs in series is calculated using the formula 1/k = 1/k1 + 1/k2. This means that the overall behavior of the system is governed by the individual spring constants rather than their sum. Understanding this relationship is crucial for accurately analyzing spring systems in physics.
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If two springs, having different spring constants, are in a series (lined up, NOT parrallel): is the Force pulling the spring = (sum of spring constants)*(distance stretched) ?
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water.
I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .